因式分解:(1)(x+y)²-4(x+y)+4(2)2a(b-c)²-3b+3c(3)x³-2x²y+xy²-x
问题描述:
因式分解:(1)(x+y)²-4(x+y)+4(2)2a(b-c)²-3b+3c(3)x³-2x²y+xy²-x
答
(1)(x+y)²-4(x+y)+4原式=(x+y)²-4(x+y)+2²=(x+y-2)²(2)2a(b-c)²-3b+3c原式=2a(b-c)²-3(b-c) =(b-c)(2ab-2ac-3)(3)x³-2x²y+xy²-x原式=x(x²-1) -xy(2x...