换元法解一元二次分式方程 2x/x²+2 + x²+2/2x = 13/6

问题描述:

换元法解一元二次分式方程 2x/x²+2 + x²+2/2x = 13/6
2x/x²+2 + x²+2/2x = 13/6

设2x/x²+2=y∴原方程可化为y+1/y=13/6∴6y²-13y+6=0∴(2y-3)(3y-2)=0∴y=3/2y=2/3∴2x/(x²+2)=3/22x/(x²+2)=2/3∴4x=3x²+63x=x²+23x²-4x+6=0...