已知定义域为R的奇函数f(x)满足f(2+x)=-f(x)则f(6)=

问题描述:

已知定义域为R的奇函数f(x)满足f(2+x)=-f(x)则f(6)=

f(6) = f(2+4) = -f(4);f(4) = f(2+2) = -f(2);f(2) = f(2+0) = -f(0);因为是奇函数,所以f(0) = 0,所以f(6) = 0