求多项式5ab^2-{2a^2b-(4ab^2-2ab^2)}的值,其中a,b,满足/a-2/+3(b+1)^2=0
问题描述：
求多项式5ab^2-{2a^2b-(4ab^2-2ab^2)}的值,其中a,b,满足/a-2/+3(b+1)^2=0
有人知道吗?
答
/a-2/+3(b+1)^2=0
a-2=0
a=2
b+1=0
b=-1
5ab^2-{2a^2b-(4ab^2-2ab^2)}
=5ab^2-2a^2b+4ab^2-2ab^2
=9ab^2-4a^2b
=18+16
=34