化简:①.(x²-y²)÷(√x+√y)= ②.a√[-(a+1)/a²]=
问题描述:
化简:①.(x²-y²)÷(√x+√y)= ②.a√[-(a+1)/a²]=
化简:①.(x²-y²)÷(√x+√y)= ②.a√[-(a+1)/a²]= ③.若0
答
①.(x²-y²)÷(√x+√y)
= (x+y)(x-y)÷(√x+√y)
=(x+y)(√x+√y)(√x-√y)÷(√x+√y)
=(x+y)(√x-√y)
②.a√[-(a+1)/a²]=
因为根号里面要大于等于0,所以:
-(a+1)>0
a+1