求过程【(x+2y)(x-2y)+4(x-y)²】÷6x (2x-3)(3x-2)-x(6x-1)+12(x-1)
问题描述:
求过程【(x+2y)(x-2y)+4(x-y)²】÷6x (2x-3)(3x-2)-x(6x-1)+12(x-1)
答
原式=(x²-4y²+4x²-8xy+4y²)÷6x
=(5x²-8xy)÷6x
=5x/6-4y/3
原式=6x²-13x+6-6x²+x+12x-12
=-6