提取公因式法(要过程和答案,详细点）(x-2y)的2次方－(x-2y)的3次方6ab(a+b)2次方－4a的2次方b(a+b)(x-y)的2次方－（y-x)的3次方(a-b)(x-y)的2次方－（a-b)(y-x)(x+y)(2p-q)-2(y+x)(2q-p)(x-1)的2次方（3x-2)+(2-3x)5m(x-y)(a-b+c)-6n(y-x)(a-b+c)已知：x2+2x-3=0且2ax2+4ax+12=0,求A的值?每一行一题,要精确答案,要详细过程.(回答对的人有高分)

1.(X-2y)^2-(X-2y)^3
=(X-2y)^2-3
=(X-2y)^-1
=1/(X-2y)
2.6ab(a+b)^2-4a^2b(a+b)
=(a+b)〖6ab(a+b)-4a^2b〗
=(a+b)〖6a^2b+6ab^2-4a^2b〗
=(a+b)〖2a^2b+6ab^2〗
=(a+b)〖2ab(ab+3b)〗
=2ab(a+b)(ab+3b)
3.(x-y)^2-(y-x)^3
=(y-x)^2-(y-x)^3
=(y-x)^2-3
=(y-x)^-1
=1/(y-x)
4.(a-b)(x-y)^2-（a-b)(y-x)
=(a-b)(y-x)^2-（a-b)(y-x)
=(a-b)(y-x)^2-1
=(a-b)/(y-x)
5.(x+y)(2p-q)-2(y+x)(2q-p)
=(x+y)〖(2p-q)-2(2q-p)〗
=(x+y)〖2p-q-4q+2p〗
=(x+y)(4p-5q)
6.(x-1)^2（3x-2)+(2-3x)
=(x-1)^2（3x-2)-(3x-2)
=(3x-2)〖(x-1)^2-1〗
=(3x-2)〖(x-1)^2-1^2〗
=(3x-2)〖(x-1)+1〗〖(x-1)-1〗
=(3x-2)·x(x-2)
=x(3x-2)(x-2)
7.5m(x-y)(a-b+c)-6n(y-x)(a-b+c)
=5m(x-y)(a-b+c)+6n(x+y)(a-b+c)
=(5m+6n)(x+y)(a-b+c)
8.x^2+2x-3=0
(x-1)(x+3)=0
x1=1,x2=-3
当x=-3时,18a-12a+12=0,a=-2
当x=1时,2a+4a+12=0,a=-2
∴a1=a2=-2

1.(x-2y)^2-(x-2y)^3=(x-2y)^2(1-x+2y)
8.x^2+2x=3,
2ax^2+4ax+12=0
2a(x^2+2x)+12=0
2a*3+12=0
a=-12/6=-2

1.(x-2y)^2(2y-x+1)
2.2ab(a+b)(a+3b)
3.(x-y)^2(1+x-y)
4.(a-b)(x-y)(x-y+1)
5.-5q(x+y)
6.x(3x-2)(x-2)
7.(x-y)(a-b+c)(5m+6n)
8.a=-2

1.(x-2y)^2(2y-x+1)
2.2ab(a+b)(a+3b)
3.(x-y)^2(1+x-y)
4.(a-b)(x-y)(x-y+1)
5.-5q(x+y)
6.x(3x-2)(x-2)
7.(x-y)(a-b+c)(5m+6n)
8.因为x2+2x-3=0
所以2x2+4x-6=0
所以2x2+4x=6
因为2ax2+4ax+12=0
所以2ax2+4ax=-12
则a=-2

(X+3)(X-1)=0
X=-3或1
a=-2