化简求值:(x+2)的2次幂-(x+1) (x-1),其中x=1
问题描述:
化简求值:(x+2)的2次幂-(x+1) (x-1),其中x=1
答
(x+2)的2次幂-(x+1) (x-1)
=(x+2)^2-(x+1)(x-1)
=x^2+4x+1-(x^2-1)
=4x+2
=4*1+2=6