(40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 x^2-30X+200=0 (X-10)(X-20)=0 X-10=0 X-20=0

问题描述:

(40-x)(20+2x)=1200 800+80X-20X-2x^2=1200 -2x^2+60X-400=0 x^2-30X+200=0 (X-10)(X-20)=0 X-10=0 X-20=0
(X-10)(X-20)=0
40-x)(20+2x)=1200
800+80X-20X-2x^2=1200
-2x^2+60X-400=0
^2-30X+200=0
(X-10)(X-20)=0

分解因式
因为你把(X-10)(X-20)展开后,就等于x^2-30X+200