1/求曲线p=cos2θ在θ=π/6所对应点处的切线方程_____________
问题描述：
1/求曲线p=cos2θ在θ=π/6所对应点处的切线方程_____________
2、r=e^θ在θ=π/2处的切线方程为____________
答
θ=π/6时ρ=cos(2*π/6)=1/2,则x=ρcosθ=1/2*cos(π/6)=√3/4,y=ρsinθ=1/2*sin(π/6)=1/4参数方程为x=ρcosθ=cos2θcosθ,y=cos2θsinθ故dx/dθ=-2sin2θcosθ-cos2θsinθdy/dθ=-2sin2θsinθ+cos2θcosθ则...