根号下(7/2)^2+(1/2)^2与(根号24-根号1/2+2倍的根号2/3)-(根号1/8+根号6)
问题描述:
根号下(7/2)^2+(1/2)^2与(根号24-根号1/2+2倍的根号2/3)-(根号1/8+根号6)
答
根号下(7/2)^2+(1/2)^2=根号下(49/4+1/4)=根号下50/4=根号下[(25/4)*2]=根号下[(5/2)^2*2]=(5/2)*根号下2(根号24-根号1/2+2倍的根号2/3)-(根号1/8+根号6)=根号(4*6)-根号(2/4)+2根号(6/9)-根号(2/16)-根号6=2...