已知N2(g)+3H2(g) ←→2NH3(g) 平衡常数为K1 1/2N2(g)+3/2H2(g) ←→NH3(g) 平衡常数为K2 1/3N2(g)+H2(g)
问题描述:
已知N2(g)+3H2(g) ←→2NH3(g) 平衡常数为K1 1/2N2(g)+3/2H2(g) ←→NH3(g) 平衡常数为K2 1/3N2(g)+H2(g)
→2/3NH3(g) 平衡常数为K3
则K1、K、K3关系为:
A、K1=K2=K3 B、K1=K2*K2=K3*K3*K3
C、K1=1/2K2=1/3K3 D、K1=2K2=3K3
答
选B
1/2N2(g)+3/2H2(g) ←→NH3(g) 平衡常数为K2 ,
则反应式两边同时乘以2,平衡常数乘以二次方,则
N2(g)+3H2(g) ←→2NH3(g) k2的平方
由此可见K1=k2的平方
同理推出K1=k3的三次平方