若Ix+2I+Iy+3I=0,求2x²-y+1的值.

问题描述:

若Ix+2I+Iy+3I=0,求2x²-y+1的值.

Ix+2I+Iy+3I=0
那么x+2=0 y+3=0
x= -2 y= -3
2x²-y+1
=2×4-(-3)+1
=8+3+1
=12