求压力0.02Mpa 温度90℃蒸汽的密度?
问题描述:
求压力0.02Mpa 温度90℃蒸汽的密度?
答
PV=nRT=mRT/18,m/V=ρ=18P/[(90+273)*R]=18*0.02/(363*8.314)=0.36/3017.98=0.119285g/立方米
求压力0.02Mpa 温度90℃蒸汽的密度?
PV=nRT=mRT/18,m/V=ρ=18P/[(90+273)*R]=18*0.02/(363*8.314)=0.36/3017.98=0.119285g/立方米