xy+ 2=0,x+y-3=0求(3xy+10y))+[5x-(2xy+2y-3x)]
问题描述:
xy+ 2=0,x+y-3=0求(3xy+10y))+[5x-(2xy+2y-3x)]
答
即xy=-2
x+y=3
原式=3xy+10y+5x-2xy-2y+3x
=xy+8x+8y
=xy+8(x+y)
=-2+8×3
=22