第一题；

太多太多的题目,赚不到分数
,请分开来提问,�Ѿ���20���ˣ�Ҫô�ٸ���10�֣���������1��3a²bc��֮5a+6b+ 3bac²��֮3b-4a -3bca²��֮a+3b==(5abc+6b²c+3ab²-4a²b-abc-3b²c)/3a²b²c²=(4abc+3b²c+3ab²-4a²b)(2)��ʽ-3x²��֮y��4y³��֮x²��5xy��֮1����򹫷�ĸ��___60x²y³_____(3)��ʽx²-x��֮1��x²-2x+1��֮2x��x+x²��֮1-x����򹫷�ĸ��__x(x+1)(x-1)²______��ȫ���ش��꣬�Ҹ���40����һ�⣻��1��3a²bc��֮5a+6b+ 3bac²��֮3b-4a -3bca²��֮a+3b=(5a+6b-a-3b)/3a²bc+(3b-4a)/3abc²=��4a+3b)/3a²bc+(3b-4a)/3abc²=(4ac+3bc-3ab-4a²)/2a²bc²����Ȳ���һ�°ɣ�лл�� ������һ�� ��һ�⣻��1��3a²bc��֮5a+6b+ 3bac²��֮3b-4a -3bca²��֮a+3b=(5a+6b-a-3b)/3a²bc+(3b-4a)/3abc²=��4a+3b)/3a²bc+(3b-4a)/3abc²=(4ac+3bc-3ab-4a²)/2a²bc²�����Ϊ����Ż�ҪԼȥb(2)��ʽ-3x²��֮y��4y³��֮x²��5xy��֮1����򹫷�ĸ��____60x²y³____(3)��ʽx²-x��֮1��x²-2x+1��֮2x��x+x²��֮1-x����򹫷�ĸ��___x(x+1)(x-1)²_____��4��a-b��֮a-c +b-a��֮b-c==(a-c)/(a-b)+(c-b)/(a-b)=(a-c+c-b)/(a-b)=(a-b)/(a-b)=1��5��a²-b²��֮a +b²-a²��֮b==a/(a+b)(a-b)-b/(a+b)(a-b)=(a-b)/(a+b)(a-b)=1/(a+b) �٣�z��֮x³y��²����y��֮xz������-x²��֮yz��³=x��6�η�y²/z²��xz/y��(-y³z³/x��6�η�)=-xy��5�η�z²��2������٣�2a��֮3b²��10�η�����3b²��֮2a��10�η�=[(3b²/2a��2a/3b²)��10�η�=1 �ڣ�-c��֮a³b��²��ac��֮b����a²��֮bc)³=a��6�η�b²/c² ��ac/b��b³c³/a��6�η�=ab��4�η�c�����ʵ�̫�࣬�Ѿ�����������һ�⣻��1��3a²bc��֮5a+6b+ 3bac²��֮3b-4a -3bca²��֮a+3b=(5a+6b-a-3b)/3a²bc+(3b-4a)/3abc²=��4a+3b)/3a²bc+(3b-4a)/3abc²=(4ac+3bc-3ab-4a²)/2a²bc²�����Ϊ����Ż�ҪԼȥb(2)��ʽ-3x²��֮y��4y³��֮x²��5xy��֮1����򹫷�ĸ��____60x²y³____ (3)��ʽx²-x��֮1��x²-2x+1��֮2x��x+x²��֮1-x����򹫷�ĸ��___x(x+1)(x-1)²_____ ��4��a-b��֮a-c +b-a��֮b-c==(a-c)/(a-b)+(c-b)/(a-b)=(a-c+c-b)/(a-b)=(a-b)/(a-b)=1��5��a²-b²��֮a +b²-a²��֮b==a/(a+b)(a-b)-b/(a+b)(a-b)=(a-b)/(a+b)(a-b)=1/(a+b)�٣�z��֮x³y��²����y��֮xz������-x²��֮yz��³=x��6�η�y²/z²��xz/y��(-y³z³/x��6�η�)=-xy��5�η�z² ��2������٣�2a��֮3b²��10�η�����3b²��֮2a��10�η�=[(3b²/2a��2a/3b²)��10�η�=1 �ڣ�-c��֮a³b��²��ac��֮b����a²��֮bc)³=a��6�η�b²/c² ��ac/b��b³c³/a��6�η�=ab��4�η�c