1/1X2+1/2X3+1/3X4···+1/2006X2007(怎么做呀)

问题描述:

1/1X2+1/2X3+1/3X4···+1/2006X2007(怎么做呀)
小弟感激不尽!

1/1x2+1/2x3+1/3x4+...+1/2007
=(1-1/2)+(1/2-1/3)+(1/3-1/4)+……+(1/2007)
=1-1/2+1/2-1/3+1/3-1/4+……+1/2007
中间互相抵消
=2006/2007
参考资料:仅供参考,