(1/4)^2÷(-1/2)^3+0÷2/5-[21*(3又1/7-7又1/3)*7/22÷3/1/2]^2
问题描述:
(1/4)^2÷(-1/2)^3+0÷2/5-[21*(3又1/7-7又1/3)*7/22÷3/1/2]^2
急急急!
答
(1/4)^2÷(-1/2)^3+0÷2/5-[21*(3又1/7-7又1/3)*7/22÷3又1/2]^2=1/16÷(-1/8)+0-[21*(22/7-22/3)*7/22÷7/2]^2=-1/2-[(21÷7/2)*(1/7-1/3)*22*7/22]^2=-1/2-[6*(1/7-1/3)*7]^2=-1/2-[(6*7*1/7-6/7*1/3)]^2=-1/2...