计算:(1+2/x−x+1/x−2)÷x+4/x2−2x.

问题描述:

计算:(1+

2
x
x+1
x−2
x+4
x2−2x

原式=[

x(x−2)
x(x−2)
+
2(x−2)
x(x−2)
-
x(x+1)
x(x−2)
]•
x(x−2)
x+4

=
−(x+4)
x(x−2)
x(x−2)
x+4

=-1.