利用因式分解求x+3y=125(x≠y)时,(x2+2xy-3y2)÷(x-y)的值.
问题描述:
利用因式分解求x+3y=125(x≠y)时,(x2+2xy-3y2)÷(x-y)的值.
答
∵x+3y=125,
∴(x2+2xy-3y2)÷(x-y)=(x-y)(x+3y)÷(x-y)=x+3y=125.