解方程 (1)1/2[x-1/2(x-1)]=2/3(x-1); (2)0.1x−0.20.02−x+1/0.5=3.

问题描述:

解方程 
(1)

1
2
[x-
1
2
(x-1)]=
2
3
(x-1);
(2)
0.1x−0.2
0.02
x+1
0.5
=3

(1)去括号得:

1
2
x-
1
4
(x-1)=
2
3
(x-1),
去分母得:6x-3(x-1)=8(x-1),
去括号得:6x-3x+3=8x-8,
移项合并得:5x=11,
解得:x=2.2;
(2)方程变形得:
10x−20
2
-
10x+10
5
=3,即5x-10-2x-2=3,
移项合并得:3x=15,
解得:x=5.