函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?
问题描述:
函数y=tan﹙π/2-x﹚,x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚的值域为__?
答
x∈﹙﹣π/4,0﹚∪﹙0,π/4﹚
π/2-x∈﹙π/4,π/2﹚∪﹙π/2,3π/4﹚
y=tan(π/2-x)的值域为(-无穷,-1)∪(1,+无穷)