为什么sin2x+cos2x=2sin(2x+π/4)

问题描述:

为什么sin2x+cos2x=2sin(2x+π/4)

sin2x+cos2x=(根号下2)sin(2x+π/4)
sin2x+cos2x=(根号下2)[根号下2/2sian2x+根号下2/2cos2x]
=(根号下2)[cosπ/4sin2x+sinπ/4cos2x]
=(根号下2)sin(2x+π/4)