x分之1+y分之1=-2则x-xy+y分之3x+xy+3y

问题描述:

x分之1+y分之1=-2则x-xy+y分之3x+xy+3y

x分之1+y分之1=-2
y+x=-2xy
x-xy+y分之3x+xy+3y
=[3(x+y)+xy]/[(x+y)-xy]
=(-6xy+xy)/(-3xy)
=3分之5