若(2x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,则a-b+c-d+e-f的值=

问题描述:

若(2x+1)^5=ax^5+bx^4+cx^3+dx^2+ex+f,则a-b+c-d+e-f的值=

当x= -1
-a+b-c+d-e+f= (-1)^5 = -1
-(a-b+c-d+e-f)= -1
a-b+c-d+e-f= 1