若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?
问题描述:
若x-y不等于0,2x-3y=0,则分式(10x-11y)/(x-y)的值是()?
答
(10x-11y)/(x-y)
=[(8x-8y)+(2x-3y)]/(x-y)
=8+(2x-3y)]/(x-y)
=8+0
=8