已知3的M次方=6,9的N次方=2,则3的2M-4N+1=
问题描述：
已知3的M次方=6,9的N次方=2,则3的2M-4N+1=
答
3^(2m-4n+1)
=[(3^m)^2/(3^n)^4]*3
=[(3^m)^2/(9^n)^2]*3
=6^2/(2^2)*3
=(36/4)*3
=108/4
=27