函数y=log2(x)+logx(2x)的值域是
问题描述:
函数y=log2(x)+logx(2x)的值域是
答
y=log2(x)+logx(2x)=log2(x)+logx(2)+logx(x)=log2(x)+logx(2)+1
log2(x)与logx(2)互为倒数,故值域为(-∞,-1]∪[3,+∞)