2x-y-10=0,求代数式【(x的2次方+y的二次方)-(x-y)的二次方+2y(x-y)]÷4y的值
问题描述:
2x-y-10=0,求代数式【(x的2次方+y的二次方)-(x-y)的二次方+2y(x-y)]÷4y的值
答
2x-y=10
原式=(x²+y²-x²+2xy-y²+2xy-2y²)÷4y
=(4xy-2y²)÷4y
=(2x-y)/2
=10/2
=5