若(x-1)(x2+mx+n)=x3-6x2+11x-6,求m,n的值.
问题描述:
若(x-1)(x2+mx+n)=x3-6x2+11x-6,求m,n的值.
答
∵(x-1)(x2+mx+n)
=x3+(m-1)x2+(n-m)x-n
=x3-6x2+11x-6
∴m-1=-6,-n=-6,
解得m=-5,n=6.