化简:x-y-1分之x的平方-2xy+y的平方-1

问题描述:

化简:x-y-1分之x的平方-2xy+y的平方-1

樱桃_小纯子:
(x²-2xy+y²-1)/(x-y-1)
=[(x-y)²-1]/(x-y-1)
=[(x-y+1)(x-y-1)]/(x-y-1)
=x-y+1