求∫x/根号(1-x^2)dx的不定积分
问题描述:
求∫x/根号(1-x^2)dx的不定积分
答
答:
∫[x/√(1-x^2)]dx 令x=sint,-π/2
求∫x/根号(1-x^2)dx的不定积分
答:
∫[x/√(1-x^2)]dx 令x=sint,-π/2