如图,已知在矩形ABCD中,AB:BC=1:2,点E在边AD上,且3AE=ED. 求证:△ABC∽△EAB.
问题描述:
如图,已知在矩形ABCD中,AB:BC=1:2,点E在边AD上,且3AE=ED.
求证:△ABC∽△EAB.
答
∵ABCD为矩形,
∴∠EAB=∠ABC=90°,BC=AD.
∵AB:BC=1:2,3AE=ED,
∴AE:AB=1:2.
∴△ABC∽△EAB.