若x+y-2=0,3a²-a-2=0,求多项式5-3a²x+ax-3a²y+ay的值.
问题描述：
若x+y-2=0,3a²-a-2=0,求多项式5-3a²x+ax-3a²y+ay的值.
答
x+y-2=0
∴x+y=2
3a²-a-2=0
∴3a²-a=2
5-3a²x+ax-3a²y+ay
=5-3a²(x+y)+a(x+y)
=5-6a²+2a
=5-2(3a²-a)
=5-2×2
=1