已知y=ln(x+e^x^2) 求dy/dx
问题描述：
已知y=ln(x+e^x^2) 求dy/dx
答
y=ln(x+e^x^2) dy/dx =y'=[1/(x+e^x^2)]*(1+2xe^x^2)
已知y=ln(x+e^x^2) 求dy/dx
y=ln(x+e^x^2) dy/dx =y'=[1/(x+e^x^2)]*(1+2xe^x^2)