函数f(x)=sin(-2x+π/3)+sin2x的最大值是

问题描述:

函数f(x)=sin(-2x+π/3)+sin2x的最大值是

f(x)=-sin(2x-π/3)+sin2x
=-1/2sin2x+√3/2cosx+sin2x
=1/2sin2x+√3/2cosx
=sin(2x+π/3)
故f(x)的最大值是1