取10ml的0.05mol/lHCl溶液,加水稀释到500ml,则此溶液由水电离出的c(H+)= mol/l
问题描述:
取10ml的0.05mol/lHCl溶液,加水稀释到500ml,则此溶液由水电离出的c(H+)= mol/l
答
取10ml的0.05mol/lHCl溶液,加水稀释到500ml,则此溶液由水电离出的c(H+)= mol/l