a,b两数满足a=(根号下b-2)+(根号下2-b)+7,求a的b次方.
问题描述:
a,b两数满足a=(根号下b-2)+(根号下2-b)+7,求a的b次方.
答
根号下要满足,b-2>=0 且2-b>=0 ==> b=2 ==> a=7.
==> a^b=7^2=49.