y=【(2x+1)（2-3x）^1/3】/(x-3)^2/3求导
问题描述：
y=【(2x+1)（2-3x）^1/3】/(x-3)^2/3求导
答
y=(2x+1)(2-3x)^(1/3)(x-3)^(-2/3)
y'=(2x+1)'*(2-3x)^(1/3)(x-3)^(-2/3)+(2x+1)[(2-3x)^(1/3)]'(x-3)^(-2/3)+(2x+1)(2-3x)^(1/3)[(x-3)^(-2/3)]'
=2(2-3x)^(1/3)(x-3)^(-2/3)+1/3*(-3)*(2x+1)(2-3x)^(-2/3)(x-3)^(-2/3)-(2/3)(2x+1)(2-3x)^(1/3)(x-3)^(-5/3)
=2(2-3x)^(1/3)(x-3)^(-2/3)-(2x+1)(2-3x)^(-2/3)(x-3)^(-2/3)-(2/3)(2x+1)(2-3x)^(1/3)(x-3)^(-5/3)