lim (cosx)^ln(1/1+x^2)怎么算
问题描述：
lim (cosx)^ln(1/1+x^2)怎么算
答
lim[x→0] (cosx)^ln[1/(1+x²)]
=(cos0)^ln[1/(1+0)]
=1^ln1
=1^0
=1