9+log√2 27)(log27 4+log3√3 8)
问题描述:
9+log√2 27)(log27 4+log3√3 8)
答
(log8 9+log√2 27)(log27 4+log3√3 8)
=(2/3log2 3+6log2 3)(2/3log32+2log32)
=20/3log2 3*8/3log32
=160/9那个3√3是3次根号=(2/3log2 3+6log2 3)(2/3log32+9log32)=20/3log2 3*29/3log32=580/9