(-1/3x+3/4(y的平方))(-3/4y的平方-1/3x)计算

问题描述:

(-1/3x+3/4(y的平方))(-3/4y的平方-1/3x)计算


(-1/3x+3/4y²)(-3/4y²-1/3x)
=(3/4y²-1/3x)[-(3/4y²+1/3x)]
=-[(3/4y²)²-(1/3x)²]
=1/9x²-9/16y^4