方程组x+3y-2z=16,3x+y+4z=3,2x-5y-2z=-24
问题描述：
方程组x+3y-2z=16,3x+y+4z=3,2x-5y-2z=-24
答
x+3y-2z=16 (1)
3x+y+4z=3 (2)
2x-5y-2z=-24 (3)
(2)-(1)
2x-2y+6z=-13 (4)
(4)-(3)
3y+8z=11; (5)
(1)*2 - (3):
11y-2z=56 (6)
(5)+(6)*4
47y=235
y=5;
z=-1/2
x=0;
答
x+3y-2z=16,3x+y+4z=3,
2x-5y-2z=-24
x-8y=-40
x=8y-40
8y-40+3y-2z=16,11y-2z=56,22y-4z=112
24y-120+y+4z=3,25y+4z=123
47y=235
y=5,x=0,z=0.5
答
x+3y-2z=16(1)
3x+y+4z=3(2)
2x-5y-2z=-24(3)
(1)-(3)
8y-x=40(4)
(1)+(2)+(3)
6x-y=-5(5)
(4)×6+（5）
48y-y=235
47y=235
y=5
代入(4)
x=5×8-40=0
x=0,y=5代入（1）
15-2z=16
2z=-1
z=-1/2
x=0
y=5