f(x)=log2[1-(1/2)^x] 定义域(02是底数[1-(1/2)^x]是指数,
问题描述:
f(x)=log2[1-(1/2)^x] 定义域(0
2是底数[1-(1/2)^x]是指数,
答
f(x)=log2[1-(1/2)^x] 定义域(0
2是底数[1-(1/2)^x]是指数,