0.5mol/L的硫酸溶液ph是多少?
问题描述:
0.5mol/L的硫酸溶液ph是多少?
答
c(H+) = 2 c(H2SO4) = 2 * 0.5 = 1 mol/L
pH = - lg c(H+) = - lg 1 = 0
所以 0.5 mol/L的硫酸溶液pH为0