x2+2x+2/(x+1)=(x2+4x+6)/(x+2)-1
问题描述：
x2+2x+2/(x+1)=(x2+4x+6)/(x+2)-1
答
(x^2+2x+2)/(x+1)=(x^2+4x+6)/(x+2)-1
(x+1)+1/(x+1)=(x^2+4x+6-x-2)/(x+2)
=(x^2+3x+4)/(x+2)
(x+1)+1/(x+1)=(x+1)+2/(x+2)
1/(x+1)=2/(x+2)
x+1=(x+2)/2
x=0
答
x^2+2x+2/(x+1)=(x^2+4x+4+2)/(x+2)-1
x^2+2x+2/(x+1)=x+2+2/(x+2)-1
x^2+x-1=2/(x+2)-2/(x+1)
x(x+1)-1=-2/[(x+2)*(x+1)]
x(x+1)^2*(x+2)-x^2-3x-2=-2
x[(x^2+2x+1)(x+2)-x-3]=0
x(x^3+4x^2+5x+2-x-3)=0
x(x^3+4x^2+4x-1)=0
做到这个地方我只能得出x=0,其他的解要用公式来计算了,而且肯定有复数解,估计不是提问者的初衷吧,可能是题目掉了括号了.