求不定积分 (1-√x-1)/1+三次根号下x-1
问题描述：
求不定积分 (1-√x-1)/1+三次根号下x-1
答
设 (x-1)^(1/6)=t,则 x=1+t^6,dx=6t^5；∫[1-√(x-1)]/[1+(x-1)^(¹/³)]dx=∫[(1-t³)/(1+t²)]*(6t^5)dt=6∫(1-t-t²+t³ +t^4 -t^6)+[(t-1)/(1+t²)] dt=6t-3t²-2t³+(3t^4...