√(1-sin^2 3π/5)=cos2π/5怎麼算的?
问题描述:
√(1-sin^2 3π/5)=cos2π/5怎麼算的?
答
√[1-sin²(3π/5)]=√[cos²(3π/5)]=|cos(3π/5)|,由于3π/5>π/2,所以cos(3π/5)
√(1-sin^2 3π/5)=cos2π/5怎麼算的?
√[1-sin²(3π/5)]=√[cos²(3π/5)]=|cos(3π/5)|,由于3π/5>π/2,所以cos(3π/5)