√(1-sin^2 3π/5)=cos2π/5怎麼算的?

问题描述:

√(1-sin^2 3π/5)=cos2π/5怎麼算的?

√[1-sin²(3π/5)]=√[cos²(3π/5)]=|cos(3π/5)|,由于3π/5>π/2,所以cos(3π/5)