(3x^3y^2)^4÷(6x^2y)^2-(-1/3x^3y^2)^2·(1/2xy)^2

问题描述:

(3x^3y^2)^4÷(6x^2y)^2-(-1/3x^3y^2)^2·(1/2xy)^2

20/9 x^8y^6

原式=(81x^12y^8)÷(36x^4y^2)-(1/9x^6y^4)(1/4x^2y^2)
=9/4x^8y^6-1/36x^8y^6
=20/9x^8y^6