若(a+1)^2+4|y-6|=0,则7x+8y+4x-6y的值为?
问题描述:
若(a+1)^2+4|y-6|=0,则7x+8y+4x-6y的值为?
答
(a+1)^2+4|y-6|=0
(a+1)^2=0
4|y-6|=0
a+1=0
a=-1
4|y-6|=0
y-6=0
y=6
7x+8y+4x-6y
=11x+2y
=11x+2*6
=11x+12